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Chargers and multimeter |
Milton
Joined: Apr 23, 2005
Posts: 12
From: Sweden
PM |
Ok, this was quite an unecessary thing to do, but I have lots of old CST-13 chargers, and the voltage appear from 4.9 to 5.1 volt. As I wanted to check if my old chargers would function I did this test, just to check (want to be on the safe side). I've only tested two chargers, but I will test more. I've also would like to test my old ctr-10, but my parents have that, will test when I get hold of it. Maybe someone finds this data useful. The odd thing is the Ampere, it's 1.5A on both chargers, when it should be 450mA. Don't know why, but someone maybe has a clue on this. If you want more of this I could post, but if you find it garbage I'll stop.
Charger no1.
CST-13
Ericsson BML 162 156/1 R3A Type 4020070-BV
Input: 100-240V ~ 150mA 50-60Hz
Output: 5.1V DC 450mA
production date: 02W09
Made by Astec
Measured Volt: 5.19
Measured A: 1.51 !
Charger no2.
CST-13
Sony Ericsson BML 162 162/21 R1B Type 4020078-BV
Input: 100-240V ~ 100mA 50-60Hz
Output: 4.9V DC 450mA
production date: 05W04
Made by Salcomp
Measured Volt: 5.08
Measured Ampere: 1.50 !
Charger no3.
CST-13
Input: 100-240V ~ 70mA 50-60Hz
Output: 4.9V DC 450mA
production date: 04W44
Made by Salcomp
Measured Volt: 4.98
Measured Ampere: 1.48 !
[ This Message was edited by: Milton on 2005-05-27 00:24 ] |
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ESTOR
Joined: Apr 20, 2002
Posts: > 500
From: Singapore
PM |
the newer chargers are more efficient  |
edwardanderson
Joined: Feb 08, 2005
Posts: 13
From: Lafayette, Indiana / USA
PM |
How much of a load are you putting on the output side when measuring the load? Its hard to measure the internal resistance of the battery pack. The load stated rating is the amp's on a fully charged battery pack. I am sure if you measure it durring the charging of a fully charged battery it will be within specification. I do not know why but I read somewhere this is reason.
"Its not what you know, its who you steel it from"
k700i R2CA001 (from Davinci)
prgCXC125821_EU_1_C
CDA 102337/15 R6A |
ijefferies
Joined: Dec 24, 2004
Posts: 201
PM |
Did you measure these voltages and currents as an open circuit or whilst connected to phone? How did you connect the meter to the charger? Just curious as I've also done a similar thing! |
ijefferies
Joined: Dec 24, 2004
Posts: 201
PM |
Ah, just reread the post. I think you're connecting the meter across the charger with no load or resistance. Not a good idea as things will get hot! Always connect the ammeter in series and the voltmeter in parallel.
[ This Message was edited by: ijefferies on 2005-05-27 19:38 ] |
Milton
Joined: Apr 23, 2005
Posts: 12
From: Sweden
PM |
I measured without any resistance and without battery. Thought that the output specified was the actual output without battery connected or anything else. |
blackspot
Joined: Sep 06, 2004
Posts: > 500
From: Philippines
PM |
You're testing the current of a circuit without a load so you are expected to get a very large reading. Theoritically a zero load should yield an infinite current.
I=V/R, where I = current, V = voltage and R = resistance, so in this case:
I = 5.0 volts / 0 ohms = infinite amperes
edit: In real life, infinite amperes is unattainable, the reading of 1.5 Amperes (approx) is just the maximum your charger can handle.
_________________
resistance is futile.
[ This Message was edited by: blackspot on 2005-05-31 02:33 ] |
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Posted: 2005-05-26 23:36
