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Author Maths question! some1 plz tell me how to go about it!
marceta
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Posted: 2004-10-16 04:33
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Hello all. I need to "build" a bridge over a canyon. The task is to determine the minumum length of the bridge, by finding the length of the canyon. I have no measurments and am told to use trigonometry and bearings!

anything will be greatly appreciated! many thx in advance!
artemiy
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Posted: 2004-10-16 05:05
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What instruments do you have?

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Posted: 2004-10-16 12:23
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what level is this question??? GCSE?
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kimcheeboi
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Posted: 2004-10-16 12:42
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well what kind of bridge?

for an arc bridge ts prolly some function of sin(x)

or you can just draw a straight line

arc length formula:



y= sqrrt((r-x^2)) if youre gonna use a hlaf circle

why dont you post the q? up in hurrrrr so we can see it? Damnit im incoherent again!

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[ This Message was edited by: kimcheeboi on 2004-10-16 11:51 ]
Ayush
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Posted: 2004-10-16 13:08
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Lol i was never good at math

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Posted: 2004-10-16 13:27
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nah, i dont think this is a GCSE question, because i was in higher last year and we didnt get any of this crap, lol

but he could be using and different exam bord.


im also quite intrested on how its done, lol
Sage
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Posted: 2004-10-16 14:29
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bearings and trig seem to be to me GCSE level.

With what you've given us, its impossible to tell the length of the bridge. Perhaps there is a diagram or measurement you've forgotten?
*Jojo*
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Posted: 2004-10-16 16:56
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@marceta - Maybe 'google' can just help you here !

@kimcheeboi - Are you dead serious with your 'formula' back there mate? I never thought that you are good in solving mathematical problems? I thought your 'forte' is - "Geography" - island hopping !
artemiy
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Posted: 2004-10-16 17:39
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[ This Message was edited by: artemiy on 2004-10-16 16:46 ]
marceta
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Posted: 2004-10-17 04:32
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thank you soo much, u r a champion! however i do not really get L = A * "tg(a)" !

Tan is Opposite/Adjacent, and in this case, tan of a is L/A, so the equation would no work out? can u plz explain the formula a little bit better. thx again!
kimcheeboi
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Posted: 2004-10-17 06:36
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tan(<a)=L/A

solving for L

L=A*tan(<a)

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[ This Message was edited by: kimcheeboi on 2004-10-17 05:39 ]
artemiy
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Posted: 2004-10-17 06:49
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Yes. Kim is right. Because L/A = tg This message was posted from a Nokia
marceta
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Posted: 2004-10-18 00:08
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Quote:
tan(
solving for L

L=A*tan(


??? thx for tryin kim, but that explaination is a little harder than the first :s !

1) tan (2) how can the length of L = length of A x Tan(a)[tan a involves L neway, L cannot be on 2 sides of the equation?)

sorry my studpidness, but in AUS we do things just a tad different!
kimcheeboi
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Posted: 2004-10-18 00:17
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a is already known, and angle a is already known too.

so if you solve for a, it still works out.

Basically you're setting L/A=L/A, and sincve L/A=tan(a) L/A=tan(a)

kinda like chemistry and physics laws :-/ [addsig]
marceta
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Posted: 2004-10-18 04:17
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Quote:
a is already known, and angle a is already known too.

so if you solve for a, it still works out.

Basically you're setting L/A=L/A, and sincve L/A=tan(a) L/A=tan(a)

kinda like chemistry and physics laws :-/


thx a lot, that cleared it up. would have been easy if i did chemistry and physics i guess!
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