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Author The Maths Thread!
maddav
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Posted: 2004-10-21 22:57
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That's it, i remembered something!

it's about rotating across the x axis on 2 hyperbola, but I can't remember, i know you eventually you get the infinite surface area, and finite volume.

I remembered our physics teacher that was going on about theories of the 'shape' of the universe, and he expained the gabriel's horn shape, and we were asking if that was A-level, he said no, and that it was just kind of interesting..

well he was right

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[ This Message was edited by: maddav on 2004-10-21 22:08 ]
kimcheeboi
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Posted: 2004-10-21 23:13
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Sure, post your own problems! I'll post some linear algebra and differential eqs too if anyone wants. Btw to win the #1 you need to use 2 integrals. Very simple problem. ;-)

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mixin
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Posted: 2004-10-21 23:15
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I passed my A-level Maths 2 and a half years ago. Now managed to wipe all of it from the brain
RichLok
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Posted: 2004-10-21 23:19
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This is as far as I got in math... and that's by watching an episode of "The Simpsons". The one with Barney (The purple dinosaur) on it...

"Two plus two is four.... Two plus two is four... Two plus two is four...:"

kimcheeboi
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Posted: 2004-10-22 00:39
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here's a good one!

A series circuit contains a resistor with R= 40 ohms, an inductor with L=2H, a capacitor with C=0.0025 F, and a 12-V batter. The initial charge is Q=.01C and the initial current is 0. Find the charge at time t.

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maddav
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Posted: 2004-10-22 00:41
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This is an easy one I did a couple of weeks ago, so it should be REALLY EASY for you lot!

Solve the equation to find the co-ordinates of each intersection

x(x-3) = x^2(1-x)


@Kimcheeboi: Damn, I can't do it, you seem to be posting all questions just out of my grasp, haven't covered inductors etc. in physics yet!


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[ This Message was edited by: maddav on 2004-10-21 23:43 ]
kimcheeboi
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Posted: 2004-10-22 00:59
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x=plus or minus sqrrt or 3 or 0

@maddav

fine!

here ya go:

integrate:
x^3/(4x^2+9)^(3/2)

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maddav
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Posted: 2004-10-22 01:01
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almost there Kim, but i said co-ordinates

kimcheeboi
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Posted: 2004-10-22 01:07
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i wasn't paying attention

btw how are you supposed to find the coordinates of a linear equation? it's not even on a plane!

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"conspiraqcy theories"-meths
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[ This Message was edited by: kimcheeboi on 2004-10-22 00:08 ]
maddav
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Posted: 2004-10-22 01:21
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OK, I'm really tired and I missed out the VERY top part of my notes (the y's), but i think this is what i did (that's re-assuring )

y=x(x-3)
y=x^2(1-x)

you should end up with what you got

(x)(x^2-3)

therefore y= (x)(x^2-3)

when x =0, y = 0

when x = +rt3

y= (rt3)(3-3)

y= 3-3rt3 or 3(1-rt3)

and the same for -rt3, i would do it, but I've got to go to bed now.

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[ This Message was edited by: maddav on 2004-10-22 00:34 ]
maddav
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Posted: 2004-10-28 18:48
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@anyone:
I've got some homework, and i solved this question, but the book says I'm wrong our teacher said there was a number of mistakes in it as well, so it's really annoying. Anyway, here it is, just the y values please, haven't bothered solving the x values yet.

Simultaneous equations:

x=2y-2
x^2 = y^2 +7

Thanks!

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[ This Message was edited by: maddav on 2004-10-28 18:22 ]
50Cent
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Posted: 2004-10-28 19:08
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x=2
y^2= -3

if u want explanation ask (check my answers with the books and urs)

Explanation:
take
x=2y-2 and square it

x^2=4y^2-2
x^2=y^2+7

rearrange

x^2 - 4y^2=-2
x^2 - y^2=7

subtract

-3y^2=9
divide by -3
y^2=-3

substitue into x^2=y^2+7

x^2= -3 +7
x^2=4
x=2

i'm probably wrong as always but its my offering

50

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[ This Message was edited by: 50Cent on 2004-10-28 18:08 ]

[ This Message was edited by: 50Cent on 2004-10-28 18:15 ]
BobaFett
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Posted: 2004-10-28 19:09
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When i was in general school, it was a usually question of math teachers to students: a ship is 55 m long and there are 273 passangers on board. How old is the captain?

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50Cent
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Posted: 2004-10-28 19:19
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thats a tough one just gimme a month to find a 55m boat that has a 279 passenger capacity den i'll just ask the captain
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maddav
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Posted: 2004-10-28 19:20
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@boba:

@50: Ummm, it's a simultaneous equation, with an x^2 and y^2 values, so there should be 2 values for x. This is what i got:

x = 2y-2
x^2 = y^2 + 7


Substitute the value for x, into the second equation:

(2y-2)(2y-2) = y^2 + 7

= 4y^2 -4y -4y +4 = y^2 +7

= 3y^2 - 8y -11 = 0

= (y+1)(3y-11) = 0

y+1=0 y=-1

OR

3y-11=0 y=11/3
3y=11
y=11/3


That's the y values but the book has y=3 or -1/3
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